On Sat, May 3, 2025 at 05:45 AM, Cheng Fei Phung wrote:
That is a huge change!
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The fact that you moved the ground is insignificant.? It just shifts the voltages.? But you are no longer powering the "VN" net with a voltage source that had the polarity wrong, and that is a significant change.
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Not having studied the IEEE article, I wasn't sure but I suspected that the purpose of the "Output voltage regulator" section (and your M32) was to derive a regulated DC voltage on node VN.? And it looks like that is finally working now, in this schematic.? The earlier schematics you uploaded had that wrong, both by driving VN with a separate voltage source and by giving it the wrong polarity.
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However, I would not expect much difference in circuit performance at this stage.? The oscillator is the part of the circuit way over on the left, and everything else in the schematic is superfluous, except for the DC biasing voltages on nodes "g_a" and "g_b".? The output amplifier is just an output buffer and you could have omitted it because it is not part of the oscillator.? It adds a little load on the "Q1" net but I think that could be mostly ignored.
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What do you hope to achieve by sweeping the supply voltage, V_1?? Does it give you any significant information about the operation of the circuit?? In the end it does, after everything is working.? It tells you about things like supply voltage "pull".? But until the circuit oscillates, I think sweeping V_1 does not give you any useful information.
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I think I might be more interested in sweeping the DC voltage at the input of the oscillator's amplifier (node "M1_gate") and examining what is the transfer function and signal gain of M1.? That gain is what makes the oscillator oscillate - or perhaps why it does not oscillate.? Perhaps you should be looking there.
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I am now interpreting the underlying theory, I will get back to you next week with details.
That's good - but why have you not considered much of the advice you were given?? It seems to me that you are not very interested in trying to get your circuit right.? Do I read that incorrectly?
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Andy
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