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Re: Parsing a string

Dave wo2x All Messages By This Member #1435 开云体育 Mick has an extra msg.out. Only need 0 – 7. ? Here’s a flow using split/switch/function to give false (0) or true (1) for each bit. First bit is top function node and last bit is bottom. Then feed into GPIO node. ? Dave wo2x ? [ ??? { ??????? "id": "4e7a77e9.defc48", ??????? "type": "tab", ??????? "label": "Flow 2", ??????? "disabled": false, ??????? "info": "" ??? }, ??? { ??????? "id": "cd5a6a57.fb77d8", ??????? "type": "inject", ??????? "z": "4e7a77e9.defc48", ??????? "name": "", ??????? "props": [ ??????????? { ??????????????? "p": "payload" ??????????? } ??????? ], ??????? "repeat": "", ??????? "crontab": "", ??????? "once": false, ??????? "onceDelay": 0.1, ??????? "topic": "", ??????? "payload": "01010101", ??????? "payloadType": "str", ??????? "x": 300, ??????? "y": 220, ??????? "wires": [ ??????????? [ ??????????????? "fe4dc4d6.037c98" ??????????? ] ??????? ] ??? }, ??? { ??????? "id": "dd5611e4.15976", ??????? "type": "function", ??????? "z": "4e7a77e9.defc48", ??????? "name": "", ??????? "func": "if (msg.payload == \"1\") {\n??? msg.payload = \"true\";\n} else msg.payload = \"false\";\n\nreturn msg;", ??????? "outputs": 1, ??????? "noerr": 0, ??????? "initialize": "", ??????? "finalize": "", ??????? "x": 760, ??????? "y": 160, ??????? "wires": [ ??????????? [] ??????? ] ??? }, ??? { ??????? "id": "3ed35afa.0a1936", ??????? "type": "switch", ??????? "z": "4e7a77e9.defc48", ??????? "name": "", ??????? "property": "parts.index", ??????? "propertyType": "msg", ??????? "rules": [ ??????????? { ??????????????? "t": "eq", ??????????????? "v": "0", ??????????????? "vt": "num" ??????????? }, ??????????? { ??????????????? "t": "eq", ??????????????? "v": "1", ??????????????? "vt": "num" ??????????? }, ??????????? { ??????????????? "t": "eq", ??????????????? "v": "2", ??????????????? "vt": "num" ??????????? }, ??????????? { ??????????????? "t": "eq", ???????? ???????"v": "3", ??????????????? "vt": "num" ??????????? }, ??????????? { ??????????????? "t": "eq", ??????????????? "v": "4", ??????????????? "vt": "num" ??????????? }, ??????????? { ??????????????? "t": "eq", ??????????????? "v": "5", ??????????????? "vt": "num" ??????????? }, ??????????? { ??????????????? "t": "eq", ??????????????? "v": "6", ??????????????? "vt": "num" ??????????? }, ??????????? { ??????????????? "t": "eq", ??????????????? "v": "7", ??????????????? "vt": "num" ??????????? } ??????? ], ??????? "checkall": "true", ??????? "repair": false, ??????? "outputs": 8, ??????? "x": 600, ??????? "y": 280, ??????? "wires": [ ??????????? [ ??????????????? "dd5611e4.15976" ??????????? ], ?????????? ?[ ??????????????? "b656e3bc.3661f" ??????????? ], ??????????? [ ??????????????? "b3ccafd3.6efc2" ??????????? ], ??????????? [ ??????????????? "65512697.166d98" ??????????? ], ??????????? [ ??????????????? "e6171e3d.e5f4d" ??????????? ], ??????????? [ ??????????????? "96d14c2b.9798e" ??????????? ], ??????????? [ ??????????????? "ccbba3c4.d57db" ??????????? ], ??????????? [ ??????????????? "4916a72a.09bbc8" ??????????? ] ??????? ] ??? }, ??? { ??????? "id": "fe4dc4d6.037c98", ??????? "type": "split", ??????? "z": "4e7a77e9.defc48", ??????? "name": "", ??????? "splt": "1", ??????? "spltType": "len", ??????? "arraySplt": 1, ??????? "arraySpltType": "len", ??????? "stream": false, ??????? "addname": "", ??????? "x": 450, ??????? "y": 220, ???? ???"wires": [ ??????????? [ ??????????????? "3ed35afa.0a1936" ??????????? ] ??????? ] ??? }, ??? { ??????? "id": "b656e3bc.3661f", ??????? "type": "function", ??????? "z": "4e7a77e9.defc48", ??????? "name": "", ??????? "func": "if (msg.payload == \"1\") {\n??? msg.payload = \"true\";\n} else msg.payload = \"false\";\n\nreturn msg;", ??????? "outputs": 1, ??????? "noerr": 0, ??????? "initialize": "", ??????? "finalize": "", ??????? "x": 760, ??????? "y": 200, ??? ????"wires": [ ??????????? [] ??????? ] ??? }, ??? { ??????? "id": "b3ccafd3.6efc2", ??????? "type": "function", ??????? "z": "4e7a77e9.defc48", ??????? "name": "", ??????? "func": "if (msg.payload == \"1\") {\n??? msg.payload = \"true\";\n} else msg.payload = \"false\";\n\nreturn msg;", ??????? "outputs": 1, ??????? "noerr": 0, ??????? "initialize": "", ??????? "finalize": "", ??????? "x": 760, ??????? "y": 240, ??????? "wires": [ ??????????? [] ??????? ] ??? }, ??? { ??????? "id": "65512697.166d98", ??????? "type": "function", ??????? "z": "4e7a77e9.defc48", ??????? "name": "", ??????? "func": "if (msg.payload == \"1\") {\n??? msg.payload = \"true\";\n} else msg.payload = \"false\";\n\nreturn msg;", ??????? "outputs": 1, ??????? "noerr": 0, ??????? "initialize": "", ??????? "finalize": "", ??????? "x": 760, ??????? "y": 280, ??????? "wires": [ ??????????? [] ??????? ] ??? }, ??? { ??????? "id": "e6171e3d.e5f4d", ??????? "type": "function", ??????? "z": "4e7a77e9.defc48", ??????? "name": "", ??????? "func": "if (msg.payload == \"1\") {\n??? msg.payload = \"true\";\n} else msg.payload = \"false\";\n\nreturn msg;", ??????? "outputs": 1, ??????? "noerr": 0, ??????? "initialize": "", ??????? "finalize": "", ??????? "x": 760, ??????? "y": 320, ??????? "wires": [ ??????????? [] ??????? ] ??? }, ??? { ??????? "id": "96d14c2b.9798e", ??????? "type": "function", ??????? "z": "4e7a77e9.defc48", ??????? "name": "", ??????? "func": "if (msg.payload == \"1\") {\n??? msg.payload = \"true\";\n} else msg.payload = \"false\";\n\nreturn msg;", ??????? "outputs": 1, ??????? "noerr": 0, ??????? "initialize": "", ??????? "finalize": "", ??????? "x": 760, ??????? "y": 360, ??????? "wires": [ ??????????? [] ??????? ] ??? }, ??? { ??????? "id": "ccbba3c4.d57db", ??????? "type": "function", ??????? "z": "4e7a77e9.defc48", ??????? "name": "", ??????? "func": "if (msg.payload == \"1\") {\n??? msg.payload = \"true\";\n} else msg.payload = \"false\";\n\nreturn msg;", ??????? "outputs": 1, ??????? "noerr": 0, ??????? "initialize": "", ??????? "finalize": "", ??????? "x": 760, ??????? "y": 400, ??? ????"wires": [ ??????????? [] ??????? ] ??? }, ??? { ??????? "id": "4916a72a.09bbc8", ??????? "type": "function", ??????? "z": "4e7a77e9.defc48", ??????? "name": "", ??????? "func": "if (msg.payload == \"1\") {\n??? msg.payload = \"true\";\n} else msg.payload = \"false\";\n\nreturn msg;", ??????? "outputs": 1, ??????? "noerr": 0, ??????? "initialize": "", ??????? "finalize": "", ??????? "x": 760, ??????? "y": 440, ??????? "wires": [ ??????????? [] ??????? ] ??? } ] ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? toggle quoted message Show quoted text From: [email protected] <[email protected]> On Behalf Of Mick - W8BE Sent: Friday, January 29, 2021 3:01 PM To: [email protected] Subject: Re: [nodered-hamradio] Parsing a string ? Here is a function to split the input and output a msg for each bit.? ?I used a string of 10000000 as the inject ? ? The output gives you the msg.payload and msg.topic ? Here is the function. ? var output = msg.payload.split(""); msg.out0 = parseInt(output[0]); msg.out1 = parseInt(output[1]); msg.out2 = parseInt(output[2]); msg.out3 = parseInt(output[3]); msg.out4 = parseInt(output[4]); msg.out5 = parseInt(output[5]); msg.out6 = parseInt(output[6]); msg.out7 = parseInt(output[6]); msg.out8 = parseInt(output[7]); msg.out9 = parseInt(output[8]); msg1 = {topic: 'Bit 1',payload:msg.out0}; msg2 = {topic: 'Bit 2',payload:msg.out1}; msg3 = {topic: 'Bit 3',payload:msg.out2}; msg4 = {topic: 'Bit 4',payload:msg.out3}; msg5 = {topic: 'Bit 5',payload:msg.out4}; msg6 = {topic: 'Bit 6',payload:msg.out5}; msg7 = {topic: 'Bit 7',payload:msg.out6}; msg8 = {topci: 'Bit 8',payload:msg.out7}; msg9 = {topic: 'Bit 9',payload:msg.out8}; node.send(msg1); node.send(msg2); node.send(msg3); node.send(msg4); node.send(msg5); node.send(msg6); node.send(msg7); node.send(msg8); node.send(msg9); return; You could then run this into a switch node for further?processing or just modify it by creating a var instead of msg and then process it in the function.? ? On Fri, Jan 29, 2021 at 1:53 PM David De Coons wo2x <RocketNJ@...> wrote: Neal beat me to it. ? Split/Switch is the way to go. Easy. ? 73 Dave wo2x ? ? From: [email protected] <[email protected]> On Behalf Of Neal Pollack Sent: Friday, January 29, 2021 1:38 PM To: [email protected] Subject: Re: [nodered-hamradio] Parsing a string ? Another way to split the outputs; ? ? On Fri, Jan 29, 2021 at 10:24 AM Michael Walker <va3mw@...> wrote: I have a workable solution ? (Dave, no driving and texting)? :) ? Take the string and convert it to csv.? I can manage the rest.?? ? But, I will like to see your idea. ? 73 ? ? On Fri, Jan 29, 2021 at 1:17 PM David De Coons wo2x <RocketNJ@...> wrote: I’ve got a solution. I should be home in 1/2 hr. ? Dave wo2x ? ? Sent from my waxed string and tin cans.? ? On Jan 29, 2021, at 1:11 PM, Michael Walker <va3mw@...> wrote: ? Hi Neal ? Yes, that is the status of 8 relays that I need to break out so I can build an LED panel (so to speak) ? Mike? ? On Fri, Jan 29, 2021 at 1:09 PM Neal Pollack <nealix@...> wrote: Mike: ? I don't have the actual answer, but I think I understand how to describe what you want: ? Given a binary string of 1's and 0's such as, for example, 10010110 , parse out each digit position, and assign?each digit to a separate boolean variable name set to 1 or 0.? ? Is that what?you're looking for? ? Neal ? On Fri, Jan 29, 2021 at 9:52 AM Michael Walker <va3mw@...> wrote: Hi All ? I have a string I need to parse of 8 binary values being returned from a relay board ? 10000000 ? What is the best way to parse out the status of each of these relays??? ? I looked at 'string' but I can't see a method that allows me to pull the boolean out 1 at a time. ? thoughts? ? Mike va3mw ?

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#1435

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