Using the NanoVNA with an identical setup I get 11 ohms -j49 ohms. Which is pretty
useless. What is going on ?
Indeed 442 pF at 7.2 MHz, that's 0-j50 ohms No need for software to calculate that.
Z=1/Cw where
w=2*pi*F
C in Farad
F in Hz
pi 3.14
If with your NanoVNA you read: 11 ohms -j49 ohms, it's probably because you have badly calibrated your nanoVNA. You have to do OSL at the location where you place your capacitor
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Fran?ois
-----Message d'origine-----
De la part de Stewart Baker
Envoy¨¦ : samedi 8 mars 2025 15:51
