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DC wall transformers

d nixon
 

Why is it that wall transformers don't output the stated voltage? Seems to me this does nothing but cause confusion. How do I know what rating to buy?

For a project I'm working on I need a wall transformer that outputs between 14 and 16V DC. And silly me bought a 14VDC unit. But it outputs about 19V!

Is there some rule of thumb?

Argh!
-Mike



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Re: Capacitors in power supply circuits

d nixon
 

Yes, I'm interested.

-Mike


There are other IC's available for voltage regulation other than the LM3xx &
LM78xx series. I have the details somewhere around here .... (not in my
head, obviously), which provide more effective regulation for dropping large
amounts of voltage from the supply rails - with minimal heat dissapation.
Let me know if you are interested in this alternative approach and I will
endevour to find out what it is.

_________________________________________________________________
Get your FREE download of MSN Explorer at


Re: HP 772C Printer Cord

Jim Thibeault (Tebo)
 

Hi Jon:

It looks like a ferrite choke to me as well, although I talked to
two different tech's from HP and one told me that it was a diode,
and the other said that it was a current limiting resistor,
neither seemed to know for sure. I took it out of line and the
printer works great, thanks for your help, this is a great list.

Jim

Jonathan Luthje wrote:


G'day Jim,
The "thingie" that you describe sounds like an RF ferrite
choke - found
on some proprietry equipment ... beats me why it would melt
though ...
seemingly an impossibility. If it was heat-shunk (as is more
often the case)
rather than rubber encased, heat shrink is reasonably brittle
anyway and
would have cracked merely because you were trying to peel it.
I'm only
guessing of course, but I hardly think that anyone would place a
diode
inline with a power cord .... that's what PCB's are for. More
than likely a
requirement for FCC regulations or line noise reduction. It's
really
difficult to say without physically seeing it.

Sorry I couldn't be of more help.

Regards,

J0n

----- Original Message -----
From: "Jim Thibeault (Tebo)" <JIMT.KF4NBG@...>
To: <Electronics_101@...>
Sent: Thursday, August 30, 2001 9:53 PM
Subject: Re: [Electronics_101] HP 772C Printer Cord

Hi Jon,

I carefully pealed the rubber off the device and it fell apart
as
if the heat caused it to crack, I don't know what the material
was
but it looked like a choke of some kind, about 3/8 " in
diameter,
1/4 " wide and the wire was passed through it. The reason
that I
refered to it as a diode is that the tech rep from Hewlett
Packard
called it a diode, but it didn't look like any diode that I
have
ever seen.

I cut the wire back behind this device and put a new jack on
it
and it put out the required 18 volts, the printer works. Now
you
have me thinking that maybe I should insert a fuse, or fusible
link inline. Hewlett Packard won't give me any more
information,
I'be called every HP phone number that I could dig up.

Jim

Jonathan Luthje wrote:

Jim,
I would double check the device in the cord - if it got
so
hot that it
melted, it may be a fusible resistor or a thermal fuse,
designed
to prevent
fires and things of the like, if it is one of the above,
then it
would point
to a fault furthur up the line, so it may not just be a 50
cent
component,
or a power cord for that matter, it is potentially related
to a
serious
fault in your printer / power supply.

Regards,

Jon

----- Original Message -----
From: "Jim Thibeault (Tebo)" <JIMT.KF4NBG@...>
To: <Electronics_101@...>
Sent: Thursday, August 30, 2001 1:23 AM
Subject: Re: [Electronics_101] Re: Capacitors in power
supply
circuits

I need help again, I have a Hewlett Packard 722 C printer
and
there is a diode molded into the cord that goes from the
power
supply to the printer. The diode is bad and can't be
replaced
because it is molded into the cord. I would like to fix
this
problem myself because a new power supply costs $52.00 and
that is
a lot of money when a fifty cent diode is the only
problem.

Does anybody know the purpose for the diode ('s) and can I
run
the
printer by without the diode ('s). I can't tell much
about
the
diodes because the rubber is melted.

Thanks

Jim


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Re: HP 772C Printer Cord

Jonathan Luthje
 

G'day Jim,
The "thingie" that you describe sounds like an RF ferrite choke - found
on some proprietry equipment ... beats me why it would melt though ...
seemingly an impossibility. If it was heat-shunk (as is more often the case)
rather than rubber encased, heat shrink is reasonably brittle anyway and
would have cracked merely because you were trying to peel it. I'm only
guessing of course, but I hardly think that anyone would place a diode
inline with a power cord .... that's what PCB's are for. More than likely a
requirement for FCC regulations or line noise reduction. It's really
difficult to say without physically seeing it.

Sorry I couldn't be of more help.


Regards,


J0n

----- Original Message -----
From: "Jim Thibeault (Tebo)" <JIMT.KF4NBG@...>
To: <Electronics_101@...>
Sent: Thursday, August 30, 2001 9:53 PM
Subject: Re: [Electronics_101] HP 772C Printer Cord


Hi Jon,

I carefully pealed the rubber off the device and it fell apart as
if the heat caused it to crack, I don't know what the material was
but it looked like a choke of some kind, about 3/8 " in diameter,
1/4 " wide and the wire was passed through it. The reason that I
refered to it as a diode is that the tech rep from Hewlett Packard
called it a diode, but it didn't look like any diode that I have
ever seen.

I cut the wire back behind this device and put a new jack on it
and it put out the required 18 volts, the printer works. Now you
have me thinking that maybe I should insert a fuse, or fusible
link inline. Hewlett Packard won't give me any more information,
I'be called every HP phone number that I could dig up.

Jim

Jonathan Luthje wrote:

Jim,
I would double check the device in the cord - if it got so
hot that it
melted, it may be a fusible resistor or a thermal fuse, designed
to prevent
fires and things of the like, if it is one of the above, then it
would point
to a fault furthur up the line, so it may not just be a 50 cent
component,
or a power cord for that matter, it is potentially related to a
serious
fault in your printer / power supply.

Regards,

Jon

----- Original Message -----
From: "Jim Thibeault (Tebo)" <JIMT.KF4NBG@...>
To: <Electronics_101@...>
Sent: Thursday, August 30, 2001 1:23 AM
Subject: Re: [Electronics_101] Re: Capacitors in power supply
circuits

I need help again, I have a Hewlett Packard 722 C printer and
there is a diode molded into the cord that goes from the power
supply to the printer. The diode is bad and can't be replaced
because it is molded into the cord. I would like to fix this
problem myself because a new power supply costs $52.00 and
that is
a lot of money when a fifty cent diode is the only problem.

Does anybody know the purpose for the diode ('s) and can I run
the
printer by without the diode ('s). I can't tell much about
the
diodes because the rubber is melted.

Thanks

Jim


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Re: New to group and question

 


Eagle is very good. If you are using the demo version, there exists
a library for it that adds full spice simulation.

Thanks everyone for the feedback :-)

Ethan


Re: HP 772C Printer Cord

Jim Thibeault (Tebo)
 

Hi Jon,

I carefully pealed the rubber off the device and it fell apart as
if the heat caused it to crack, I don't know what the material was
but it looked like a choke of some kind, about 3/8 " in diameter,
1/4 " wide and the wire was passed through it. The reason that I
refered to it as a diode is that the tech rep from Hewlett Packard
called it a diode, but it didn't look like any diode that I have
ever seen.

I cut the wire back behind this device and put a new jack on it
and it put out the required 18 volts, the printer works. Now you
have me thinking that maybe I should insert a fuse, or fusible
link inline. Hewlett Packard won't give me any more information,
I'be called every HP phone number that I could dig up.

Jim

Jonathan Luthje wrote:


Jim,
I would double check the device in the cord - if it got so
hot that it
melted, it may be a fusible resistor or a thermal fuse, designed
to prevent
fires and things of the like, if it is one of the above, then it
would point
to a fault furthur up the line, so it may not just be a 50 cent
component,
or a power cord for that matter, it is potentially related to a
serious
fault in your printer / power supply.

Regards,

Jon

----- Original Message -----
From: "Jim Thibeault (Tebo)" <JIMT.KF4NBG@...>
To: <Electronics_101@...>
Sent: Thursday, August 30, 2001 1:23 AM
Subject: Re: [Electronics_101] Re: Capacitors in power supply
circuits

I need help again, I have a Hewlett Packard 722 C printer and
there is a diode molded into the cord that goes from the power
supply to the printer. The diode is bad and can't be replaced
because it is molded into the cord. I would like to fix this
problem myself because a new power supply costs $52.00 and
that is
a lot of money when a fifty cent diode is the only problem.

Does anybody know the purpose for the diode ('s) and can I run
the
printer by without the diode ('s). I can't tell much about
the
diodes because the rubber is melted.

Thanks

Jim


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Electronics_101-unsubscribe@...



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Re: 12 volt motor speed control

Tavys Ashcroft
 

followed by or preceded by a variable pulse-width-modulated controller
(probably something like an astable 555 driving a couple of hefty power
transistors. This all depends of course on the type of interface you intend
to feed it,
Yeah. Something like this:



-Tavys


Re: 12 volt motor speed control

Jonathan Luthje
 

Darle,
I would be tempted to have a look at the plan for the 6V controller
first up, it should be easily modified to suit 12, or even 24V, by changing
a few components. If you want to start from scratch, I would suggest a
"bridge" circuit of some type for direction reversal (either relay or
transistors - depending on whether you wanted to keep it solid-state or
not), followed by or preceded by a variable pulse-width-modulated controller
(probably something like an astable 555 driving a couple of hefty power
transistors. This all depends of course on the type of interface you intend
to feed it, but it is all very possible.

But the first thing I would do is try and modify the existing circuit, if
you would like to post it to the group then I'm sure there are a few people
(incl. myself) who would be glad to have a look at it.

Regards,

J0n

----- Original Message -----
From: <dwb4926@...>
To: <Electronics_101@...>
Sent: Thursday, August 30, 2001 9:35 AM
Subject: [Electronics_101] 12 volt motor speed control


Hello Group ,

I build scale r/c boats and I want to build my own 12 motor speed
controller to hook up to my receiver which requires a 3 wire hook up
at the receiver , wire colors = red,black,white .
I want to make an electronic speed controller with variable forward &
reverse speeds .
I have been looking for a plan to make a 12 volt speed controller but
to date I have only found a plan for a 6 volt controller ?

Can anyone help with this problem ?

Thank you for your help and time ,
Darle Bennett
dwb4926@...



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Re: 12 volt motor speed control

Darren Reid
 

From: <dwb4926@...>

I have been looking for a plan to make a 12 volt speed controller but
to date I have only found a plan for a 6 volt controller ?
I bet that it would take only a very minor change to make that circuit work
for the full 12V range. It may not require *any* change. Post a link to the
circuit and folks will surely help out.

-Darren


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Re: Capacitors in power supply circuits

Jonathan Luthje
 

Mike,

Let's assume that from your 25VA transformer you are producing an
unregulated output voltage of 28 volts (quite reasonable), and lets say that
you need to draw the full current capacity from your 5V rail (2A), now you
need to remove or regulate down 28-5 = 23V @ 2A, which is roughly 46W - say
50W for arguments sake - now 50W is a hell of a lot of heat to for a poor
'ol TO-220 flat-pack to dissapate (i.e. it can't do it, the maximum heat you
can dissapate with a 10deg/W heat sink (for example) is approximately 8.5W.
As Larry pointed out in his earlier post, if you really must use a 25VA
transformer, then a current limiting resistor needs to be applied to the
input/source pin of the LM7805. Using say a 5deg/W heatsink, which gives you
a theoretical maximum of approximately 17W. Taking 23V off the supply, we
need the Wattage

W = VA

so ...

17 = 23 * A

A = 0.73 (lets say 700mA for arguments sake)

You need to limit your 28V source to 700mA or less

V=IR ; 28=0.8 * R

A 35 ohm, or probably a 33R resistor would be the next closest value, needs
to go in front of the 7805 transistor, a 3 or 5 watt wire wound would be
preferable.

You can regulate this amount of current with one or more bypass transistors
and a large heatsink (@50W, say a 0.5 deg/W should do the job, however the
cost of implementing this outweighs the cost of just buying a reasonably
sized transformer (5-8V).

The same goes for the LM317 - another TO220 Flat-Pack, not designed to
dissapate large amounts of heat - very easy to overheat and shutdown, I had
one on a 5deg/W heatsink regulating 12V to 3V (a 9V drop), and it the
heatsink got so hot that the device shutdown (sink temp was approx 115degC -
who knows what the case temp was ... 150deg?) ... and I wasn't exactly
drawing a lot of current out of it either - 200mA or so ...

But anyway - the point is that you may need to think about the range of your
variable supply and the heatsinking capacity of your regulator, and whether
or not you will need to use bypass transistors to help spread the load.

Oh ... another point while I think of it - most of the LM317T & LM7805T
series reg's have a max current drain of 1A, so putting a 2A supply at the
other end may not be such a good idea in the first place, unless, of course
you are implementing bypass trannies.

There are other IC's available for voltage regulation other than the LM3xx &
LM78xx series. I have the details somewhere around here .... (not in my
head, obviously), which provide more effective regulation for dropping large
amounts of voltage from the supply rails - with minimal heat dissapation.
Let me know if you are interested in this alternative approach and I will
endevour to find out what it is.

I would suggest that perhaps the circuits that you have obtained are written
by people who never actually bother to build the things to check them out -
I come across a lot of circuits like that, not bad circuits fundamentally,
but a few critical errors which would prevent them from operating
effectively.

See how you go,


Regards,


J0n

----- Original Message -----
From: <dnixon9@...>
To: <Electronics_101@...>
Sent: Thursday, August 30, 2001 12:27 PM
Subject: [Electronics_101] Re: Capacitors in power supply circuits


What if I created a voltage divider at the power rails and ran the 5V
regulator off a 9V tap?

And if so, would I use low or high ohm resistors to create the
voltage divider? And why?

I appreciate the help as I'm a bit confused...I have several power
supply circuits that show a 5V regulator run right off a 25V or 36V
rail.

-Mike


Larry Hendry <hendrysr@y...> wrote:
Maybe (you decide) a decent approach might be to put a power
resistor
of small ohms (you calculate based on expected load on the source
side of the 5 volt regulator. When the current draw is low, the
high
voltage drop is not a heat problem. When the current goes up, the
voltage delivered to the regulator drops, and the power dissapated
at
the regulator is reduced (transferred to the resistor actually).



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Re: New to group and question

Darren Reid
 

From: <ethanzer0@...>

I'm new to the group and am currently working on building an analog
synthesizer. I have some good circuit designs and decent plans for
execution. My next step is PCB design. I have been using eagle for
windows and was wondering if anything better exists for doing schemes
and PCB layout.
Eagle is very good. If you are using the demo version, there exists a
library for it that adds full spice simulation.

-Darren


---
Outgoing mail is certified Virus Free.
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Version: 6.0.265 / Virus Database: 137 - Release Date: 7/18/01


Re: HP 772C Printer Cord

Jonathan Luthje
 

Jim,
I would double check the device in the cord - if it got so hot that it
melted, it may be a fusible resistor or a thermal fuse, designed to prevent
fires and things of the like, if it is one of the above, then it would point
to a fault furthur up the line, so it may not just be a 50 cent component,
or a power cord for that matter, it is potentially related to a serious
fault in your printer / power supply.

Regards,


Jon

----- Original Message -----
From: "Jim Thibeault (Tebo)" <JIMT.KF4NBG@...>
To: <Electronics_101@...>
Sent: Thursday, August 30, 2001 1:23 AM
Subject: Re: [Electronics_101] Re: Capacitors in power supply circuits


I need help again, I have a Hewlett Packard 722 C printer and
there is a diode molded into the cord that goes from the power
supply to the printer. The diode is bad and can't be replaced
because it is molded into the cord. I would like to fix this
problem myself because a new power supply costs $52.00 and that is
a lot of money when a fifty cent diode is the only problem.

Does anybody know the purpose for the diode ('s) and can I run the
printer by without the diode ('s). I can't tell much about the
diodes because the rubber is melted.

Thanks

Jim


To unsubscribe from this group, send an email to:
Electronics_101-unsubscribe@...



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Re: Capacitors in power supply circuits

 

What if I created a voltage divider at the power rails and ran the 5V
regulator off a 9V tap?

And if so, would I use low or high ohm resistors to create the
voltage divider? And why?

I appreciate the help as I'm a bit confused...I have several power
supply circuits that show a 5V regulator run right off a 25V or 36V
rail.

-Mike


Larry Hendry <hendrysr@y...> wrote:
Maybe (you decide) a decent approach might be to put a power
resistor
of small ohms (you calculate based on expected load on the source
side of the 5 volt regulator. When the current draw is low, the
high
voltage drop is not a heat problem. When the current goes up, the
voltage delivered to the regulator drops, and the power dissapated
at
the regulator is reduced (transferred to the resistor actually).


Re: New to group and question

Jonathan Luthje
 

Ethan,
Eagle is not a bad product, especially if you are not doing anything
complex. I prefer Protel layout software, but it is quite expensive just for
hobbyist work. It's expense is due to it's large component, track & layout
library, along with multi-layer, multi-sheet capability and auto-layout
features for PCB's ... quite nifty ...

You can download a demo from
Orcad is also another high-end bit of software to have a look at


Seems to be a matter or preference


Regards,


J0n

----- Original Message -----
From: <ethanzer0@...>
To: <Electronics_101@...>
Sent: Thursday, August 30, 2001 7:22 AM
Subject: [Electronics_101] New to group and question


Hello,

I'm new to the group and am currently working on building an analog
synthesizer. I have some good circuit designs and decent plans for
execution. My next step is PCB design. I have been using eagle for
windows and was wondering if anything better exists for doing schemes
and PCB layout.

Thanks,

Ethan



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Re: LEDs and relays in Autos

Jonathan Luthje
 

Jayson,
A "real" brake light (at least in this country) leaves the parking /
tail lights on simultaineously with the brake light, so the easiest way out
of it would be to just hook them up without any switching circuitry
whatsoever - load 1 to "switched", load 2 to "permanently on", if you really
wanted to switch one off and the other one on, then I would suggest that you
use a small-ish SPDT relay to switch from one to the other - hook up the
common contact to +12V, the normally closed contact to Load 2, the normally
open contact to Load 1, and the coil to "Switched +12V".

Relays are a lot more robust than transistors, especially in automotive
applications, where voltage spikes are common due to high loads on starting
/ charging etc.

Also, make sure you include current limiting resistors in your design for
the LEDs, as vehicle system voltage can be quite high during charging (up to
16V), which wouldn't do you LED's much good!

Regards,


Jon

----- Original Message -----
From: "Jayson" <woodrufj@...>
To: <Electronics_101@...>
Sent: Thursday, August 30, 2001 11:15 AM
Subject: [Electronics_101] Re: LEDs and relays in Autos


Well I'm doing something similar. I've planed out to have the "A" lit
with normal leds, while cluster "B" is super bright leds. Now i'm
trying to think of a circuit that turns A off when B goes on, check
out my previous post. This way it'll go 10% to 100% bright, more like
a real brake light.

Thanks

Jay W

--- In Electronics_101@y..., Larry Hendry <hendrysr@y...> wrote:
I'll try this again with an actual answer this time. :)

--- Jayson Woodruff <woodrufj@y...> wrote:
There are two problems I have. 1.) Both the front and
rear need to have both a low light and bright light
setting. Low for lights on, bright for blinker or
brake operation. The voltage sources I have to work
with are two 12V lines. One operates with lights on
and both are active with blinker/brake operation.
Does anyone have a better idea?
Since you are dealing with brightness caused by LED clusters, what
about making your cluster (your arrangement of series / parallel
combinations) in two parts. Not two discrete parts, but two
integrated parts. All LEDs would be the same. But, one 12 volt line
would light 50% (or some other appropriate %) of the LEDs. the
second
12 volt line would light the other 50%. So you r cluster has a "A"
and "B" light with the LED arranged like this:
ABABABABA
BABABABAB
ABABABABA

Obviously, when the second line comes on, the total brightness will
increase.

Larry H


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Re: LEDs and relays in Autos

 

Well I'm doing something similar. I've planed out to have the "A" lit
with normal leds, while cluster "B" is super bright leds. Now i'm
trying to think of a circuit that turns A off when B goes on, check
out my previous post. This way it'll go 10% to 100% bright, more like
a real brake light.

Thanks

Jay W

--- In Electronics_101@y..., Larry Hendry <hendrysr@y...> wrote:
I'll try this again with an actual answer this time. :)

--- Jayson Woodruff <woodrufj@y...> wrote:
There are two problems I have. 1.) Both the front and
rear need to have both a low light and bright light
setting. Low for lights on, bright for blinker or
brake operation. The voltage sources I have to work
with are two 12V lines. One operates with lights on
and both are active with blinker/brake operation.
Does anyone have a better idea?
Since you are dealing with brightness caused by LED clusters, what
about making your cluster (your arrangement of series / parallel
combinations) in two parts. Not two discrete parts, but two
integrated parts. All LEDs would be the same. But, one 12 volt line
would light 50% (or some other appropriate %) of the LEDs. the
second
12 volt line would light the other 50%. So you r cluster has a "A"
and "B" light with the LED arranged like this:
ABABABABA
BABABABAB
ABABABABA

Obviously, when the second line comes on, the total brightness will
increase.

Larry H


Switching circuits

 


Re: Capacitors in power supply circuits

Larry Hendry
 

--- ". ." <dnixon9@...> wrote:
And the other is a 7805T
to get the constant +5V output.
I would be somewhat concerned about using a 5V regulator from a
source voltage so high.

Jon makes a very good point (below) about the heat that will be
generated by the regulator. You really need to know how much current
you will be drawing from the regulator.

Maybe (you decide) a decent approach might be to put a power resistor
of small ohms (you calculate based on expected load on the source
side of the 5 volt regulator. When the current draw is low, the high
voltage drop is not a heat problem. When the current goes up, the
voltage delivered to the regulator drops, and the power dissapated at
the regulator is reduced (transferred to the resistor actually).

While this is not as elegant as a supply with an unregulated voltage
only a few volts above your regulator rating, it might be what you
need for this application.

From: "Jonathan Luthje" <jluthje@...>
then you would need a 35V rated transformer,
which means you need to drop 30V off your main
supply rail to achieve a +5V rail (with a
7805 reg or similar), which means that you are
going to be dissapating a LOT of heat



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Re: LEDs and relays in Autos

Larry Hendry
 

I'll try this again with an actual answer this time. :)

--- Jayson Woodruff <woodrufj@...> wrote:
There are two problems I have. 1.) Both the front and
rear need to have both a low light and bright light
setting. Low for lights on, bright for blinker or
brake operation. The voltage sources I have to work
with are two 12V lines. One operates with lights on
and both are active with blinker/brake operation.
Does anyone have a better idea?
Since you are dealing with brightness caused by LED clusters, what
about making your cluster (your arrangement of series / parallel
combinations) in two parts. Not two discrete parts, but two
integrated parts. All LEDs would be the same. But, one 12 volt line
would light 50% (or some other appropriate %) of the LEDs. the second
12 volt line would light the other 50%. So you r cluster has a "A"
and "B" light with the LED arranged like this:
ABABABABA
BABABABAB
ABABABABA

Obviously, when the second line comes on, the total brightness will
increase.

Larry H

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Re: LEDs and relays in Autos

Larry Hendry
 

--- Jayson Woodruff <woodrufj@...> wrote:
Hey Guys, I'm new here and have only very basic
knowledge of electronics. I have several wiring
projects going on with my truck and will ask mostly
that. See a little bio at the end.

I saw some post from last month about LEDs to a 12V
source and want to expand on this.

The first thing I want to build is my own LED
tail/brake lights for my truck, I don't like the
comercial ones, and their too expensive. Also I want
to build some LED front marker (blinker) lights.

If some one knows these auto systems better than I
describe then please chime in.

There are two problems I have. 1.) Both the front and
rear need to have both a low light and bright light
setting. Low for lights on, bright for blinker or
brake operation. The voltage sources I have to work
with are two 12V lines. One operates with lights on
and both are active with blinker/brake operation. The
best idea I came up with is to hook normal LEDs to the
"lights on" source and super-bright LEDs to the
"brake/blinker" source. This would light up several
low light leds for lights on, and light up several
bright leds plus the low light leds in brake/blinker
operation. Does anyone have a better idea??? I'd
prefer to use all bright LEDs because they are clear
when not on.

2.) With LEDs in place of a incandesent bulb the
blinker relay will think there is a problem and go
into "blink fast" mode. This is no good to me. I
know nothing about blinker relays, can anyone help me
with this. How can I modify the relay or line to not
detect a problem. I'm guessing that the relay is
detecting a low current when it expects a high one.
So if I got desperate I could try to dump a lot of the
current through a circuit, but this seems like a waste
of watts, and I'd have to come up with cooling
solutions. Any help would be highly appreciated.

Bio Info.

Name:
Jayson Woodruff

Location:
Orange County, California

Job:
Rocket Scientist (no joke)

Hobbies:
Mountian/Road Biking (and repair), Truck racing and
showing, soon to be racing a tiny little fiat.

Annoying Habits:
Tend to be long winded.

Jay W



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