Himanshu Sharma,
Good point! Once a capacitor is charged, the connections are removed, then
you can dismantle those plates individually without worry of reducing the
"charge" already stored in each of the plates.
This is also the proof of the statement that the energy being stored in the
plates, not in the dielectric.
Can you please explain why is the voltage increase? Increase against what?
SUNAN
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-----Original Message-----
From: Himanshu Sharma [SMTP:hs_ramdev@...]
Sent: Tuesday, October 30, 2001 1:27 PM
To: Electronics_101@...
Subject: Re: [Electronics_101] Capacitor - Charge- Energy
hey ,
here we go....thanks for the proof....
When you remove the dielectric slab then as per the formula
C=keA/d the capacitance would decrease and hence the voltage would
increase...
Since the charge is constant...Q=CV
Try that...!!
So in short the charge stays on the plates...(I did this 2 years
back..)
Regards :-),
--himanshu sharma
.
