--- In Electronics_101@..., "ghidera2000"
<ghidera2000@y...> wrote:
I'm trying to figure out at what voltage (reverse) would a 1n4148
shut off current flowing through it. e.g. 5 volt supply being
opposed by a 3.3V reverse voltage.
On the datasheet, I see Vfr - (Forward voltage recovery) at 2.5V.
Would that mean that it needs 2.5 or greater volt difference
between anode and cathode before current can flow?
Zero volts and any reverse voltage up to the maximum for a 1N4148 wil
stop current flowing though it (except for the leakage current). A
small positive voltage will produce a small current flow. For
example, at room temperature you will get 1uA of forward current at
300mV of forward voltage. At 0.675V it will be around 1mA.
Keith.