¿ªÔÆÌåÓý

Re: Henry's current transformer problem


 

Hello Henry Kafeman.
See material N41
BS (25 ¡ãC)=490mT
BS (100 ¡ãC)=390mT
Hc (25 ¡ãC)=22A/m
Hc (100 ¡ãC)=20A/m
Br=0.1T

Power
Transformer (low loss)

f<100 kHz

N27 (?i = 2000 ) low cost, hi-power
N41 (?i = 2800 ) current transformer
N51 (?i = 3000 ) loss min. @ 40¡ãC

Bordodynov.

05.08.2016, 14:27, "HKafeman hkafeman@... [LTspice]" <ltspice@...>:

analogspiceman and Andy

Thank you for your replies.

I appreciate that there are many different Ferrite materials. I do not know which specific material my CT is made of, so am looking to model a typical material.

The typical Hc value for Ferrites I found was 0.2 Oersteds.

I now realise that LTSpice uses Hc in A/m and "0.2 Oersteds = 15.9 A/m". So I need to use Hc in LTSpice of 15.9.

Sorry for the confusion about the path length (for some strange reason I was getting confused with area!) - of course it is Pi * d for the CT (with outer and inner diameters of 28.5 and 17.0mm). So in my case is 71.47mm using the average diameter, so Lm is 71.47m.

Similarly the Area for my CT (width 18mm), A is 103.5u.

Can you help me out with one other aspect of my CT please?

The manufacturer states it is rated at 0.01VA. Now I think this is the maximum Voltage * Current through the Burden Resistor.

But how does this relate to the Secondary Coil power dissipation and also dissipation in the Core?

What happens if this value is exceeded? Does it just mean that the Secondary Coil and Core are heated up significantly which affects the linearity, etc.?

Can this affect be modelled?

Thanks and Regards

Henry Kafeman

Join [email protected] to automatically receive all group messages.