On Sep 24, 2011, at 5:36 PM, teslastrike wrote:
Thanks i tried it worked, however....
What if i want to simulate now some reasonable logic, which changes
FAST. And in that case this 1uf capacitor i placed basically kills
the whole timing...
but yes, as you mentioned when i decrease capacitance i get again
3.3v on first stage...
So.. if i want to simulate some small circuit which is lets say part
of some chip where capacitances are measured in femtoFarads...its
not going to work then.
You are asking VERY much for any circuit. consider a 1uf capacitor
charged to 3.3V in 10ns. The relationship is Q = CV or I = C dV/dT. If
the current is constant for the entire charging time, then take dV =
3.3V, dT = 10ns and C = 1uF.
Then you must have I = 100 * 3.3 Amperes or 330Amperes. Any other
strategy (than constant current for the full charging time) will have
even higher currents at some point in charging cycle. The simple fact
is that charging such a large capacitor in such a short time is not
practical with "ordinary" circuits.
Jim Wagner
[Non-text portions of this message have been removed]
