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Without UIC, it runs under version 24.1.8. The input voltage is 100 V, the input current is 8 A DC plus 8A peak roughly sinusoidal (so the current goes from 0 to 16 A). The output voltage is 132 V DC and the output current is 3 A. So I think the input power is quite a lot bigger than the output power, which is not what is wanted. But I have 1 ohm in series with V9 to limit the inrush current. Without the 1 ohm, it still stalls after a few hundred microseconds, with no error message.

On Tue, May 6, 2025 at 05:33 PM, <arhamishtiaq42@...> wrote:

so do you think my primary side current is fine?

That is a somewhat difficult question for me to answer.? Maybe others can speak to this better than I can.

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But I think the answer is "yes", I think it is normal.

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Because the waveforms are not sinusoidal and the voltage and current waveforms are so very different from each other, you can not use Vrms*Irms to estimate power.? You must multiply V(time) by I(time) at every moment in time, then average the product over time.? And when you do that, you find that the power into the primary = 593 W, even though its Vrms * Irms = 95.6 * 12.9 = 1233 VA.

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(I am still wondering where you got 40 A from.? My simulations did not come close.)

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I think the only way for the primary current to be around 500 W / 100 V = 5 A, is if the transformer's primary current was also a square wave and in-phase with the voltage there.

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The energy source (V9) provides 597 W, the transformer passes 593 W, and the load (R1) dissipates 458 W.? These are from simulating your third schematic, dd.asc, without UIC, and waiting until after the initial transients die out.

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Andy

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