On Wed, May 7, 2025 at 12:00 AM, Tony Casey wrote:
.MEAS MaxdV max d( I(L_filter_dc)) ; max +v derivative
.MEAS T1 when d( I(L_filter_dc))=0.98*MaxdV rise=1 ; start of 1st +ve transition
.MEAS MindV min d( I(L_filter_dc)) ; max -ve derivative
.MEAS T2 when d( I(L_filter_dc))=0.98*MindV fall=1 ; start of 1st -ve transition
.MEAS T3 when d( I(L_filter_dc))=0.98*MaxdV td=T2 rise=1 ; start 2nd +ve transition
Dear Tony,
?
Thank you for answering again.
I believe I will have to finding the maximums and minimums localized to a specific time interval (example: 10 ms to 11 ms) and then do the rest. Your answer too is a clever solution just like what Andy suggested, however, with a different approach and a little bit of tweaking at my end because the inductor current rises and falls exponentially (due to parasitics).
With Regards,
Ankit
