Re: Adjusting Bode plot phase
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Jerry wrote:
? ? "The Bode plot of the input impedance shows a phase shift of 0 to -45 degrees, but the expected result is -45 to -90 degrees."
The impedance plot that I see goes from 0 to -90 degrees.
FYI, if you change V1 to AC 1V, it makes things easier.? Then the impedance equals the inverse of current.? Be careful about current directions, and voltage polarity.? If you plot the inverse of the current through V1, its current flows internally from?+ to -, which means it is externally from its - to?+ pins.? Note the arrow of the red current "probe" arrow in LTspice.
The impedance must start at 0 degrees at DC (very low frequencies).? It can't be constrained between -45 and -90 degrees, unless you mean over a limited frequency range.? Do you have a reference that says the impedance must be between -45 and -90 degrees?? Might that reference be wrong?? Or does it have qualifiers (such as, only between 10kHz and 1MHz)?
By the way, when uploading files, please upload only to the "Temp" folder.? (You didn't, but it's been fixed.)
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To do that, FIRST navigate to that folder, and only THEN click the Upload button.
Regards, Andy
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