And S11 (vector) is indeed identical to Gamma (vector), or S11 and the Reflection Coefficient
are one and the same.
Hello
** I agree gamma=S11 **
In effect
If we use Z = Zo * (1+gamma) / (1-gamma) that means:
Zo + Zo.gamma = Z - Z.gamma
gamma.(Zo+Z) = Z - Zo
gamma = (Z-Zo)/(Z+Zo)
But the question was how to calculate S11 from the impedances and you didn't explain how you calculated gamma if Z=A+jB
Your formulation gamma = (Z-Zo)/(Z+Zo) misled me and stupidly I thought it meant
gamma (A-Zo)/(A+Zo) + j (B-Zo)/(B-Zo)
To answer the question, if the impedance is Z=A+jB it is necessary to continue the development of gamma = (Z-Zo)/(Z+Zo) and that gives:
gamma = (A?+B?-Zo?+2jBZo) / ((A+Zo)?+B?)
Is this correct ?
It is indeed a pity that nanovna-saver only indicates |S11| on the screen. You have to go to the .S1P file to find
S11 = a+jb
a and b are then the coordinates of the point representing the impedance in the Smith diagram (xOy mark centered on the chart with the unit corresponding to the large outer circle).
x=a and y=b
Is this correct ?
Sorry to have contradicted you by mistake but, in addition, my language is French and I have to make BIG efforts to write in English (thanks Google). I am not a teacher but an old OM who tries to find his way between what he measures (with his nanoVNA-F + nanovna-saver), what he calculates as an adapter for example, what he realizes practically and the observed results (measurements).
--
F1AMM (Fran?ois)
-----Message d'origine-----
De la part de AG6CX (Edward San Francisco)
lundi 25 juillet 2022 00:58
