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Lets look at some of the mathamatical relationships: C = capacitance in Farads Q = charge in Coulohms V = voltage in Volts I = current in amperes t = time in seconds C = Q/V I = Q/t or Q = I t

There are LEDs out there that blinks by themself. I think you supply them with 3V or 5V or something and it has all the electronics built in them. They look like regular LEDs. Check with digikey or

Sunantoro, As long as we are splitting hairs, [whop, one rabbit into two] You can have a magnetic field in an inductor but not in inductance. Inductance is a property that induces voltage in a

Sunantoro, Don't think any electrons accumulate on the plates. Where would they stay. I'm thinking now that charge is the wrong term to use for the resulting stored energy. We often say that a

Jim, No that was not my point, correct or not I was saying that the energy is stored in the e.s. field not on the plates or in the dielectric. Just energy stored in an inductor is stored in the mag.

d nixon, Hmm... Where was the ground when this capacitor was charged. Did that change. Too many loose ends to predict. My first reaction was that this would be two series caps, which I think it is,

Mike, When you say "magnetic field" do you mean it the magnetic field in the inductance issue? SUNAN

Neal, Sound like a split hair to me. How does the field get through the dielectric without being in it. If the dielectric is swapped after the original charging voltage is removed, will the field

Sorry to have inadvertently click the "send" button when it should have been the "save" button. Those two button are located side by side on my PC. When people discuss about capacitor, they use

"J. Pinkston", Here's my prediction of what will happen, although you may not be able to detect this. When the paper is between the plates there will be a charge of so many coulombs. When you remove

Doug, Cook seemed to fall short of saying that. First off, the charge he referred to was not the resulting stored energy but that what produced the storage in the first place. OK, I see that. Now,

Rama,

Another interesting experiment would be to insert a metal plate inside the dielectric so that you have: plate-dielectric-plate-dielectric-plate. The middle plate (ground it?) should prevent any

Ah, so it's the field that stores all the energy? And fields, like any EM radiation, don't need a medium. When the field collapses the energy is transmitted to the plates, which goes through the

No, the key is how much money some fool is willing to pay for such a device. Package it with a new diet and you've got yourself a money-maker. -Mike

http://www.uoguelph.ca/~antoon/circ/ledflash.htm http://www.uoguelph.ca/~antoon/gadgets/bfflash2.htm http://www.reprise.com/host/circuits/flasher.asp

Some snippage and comments below:

I don't understand it either but the Navy training manuals agree with Jim. I think I'm going to try an experiment when I g

Jim Purcell wrote: facts but do not apply in order to something I may is wrong. While I doing is trying to difficulties, then of 'where a college level physics, I have often had question them or to

I have designed with both but have never done the replacement. I shouldn't be hard - they work the same way. Doug Budijanto S wrote: