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LED Flasher?

 

I'd like to build a flashing LED strobe for my recumbent bike. Are
there any kits or How-To books I might use?
I would like to use several led's mounted on the flag whip with power
source and as much components as possible on the frame.
Most of what I find are way too big and/or expensive.
I have minimal electronics experience but can follow directions and
have built some kit radios and similar stuff.


Re: The need to know!

Doug Hale
 

Yes Jim, You've got it.

Charge(voltage) and Electric field are to a capacitor what
Current and Magnitic field are to an inductor.

Doug Hale




Jim Purcell wrote:

Why is as important as What. When If I know a collection of facts but do not
understand why they are so, I have no principles that I can apply in order to
apprehend other facts. So when struggling to understand something I may
appear to be arguing, as in stating that the other person is wrong. While I
have been known to do that some times, usually what I'm doing is trying to
get my mind around the facts.

That I never took college level physics may explain my difficulties, then
again maybe not since I don't know to what extent the issue of 'where a
charge is stored in a capacitor, might be answered by college level physics,
at least as much of it as an EE might take. As a technician I have often had
to just accept some premise, not having the knowledge to question them or to
verify them for that matter. And being pragmatic I see no problem with that
as long is it doesn't interfere with what I may be trying to do. For
example, who care which convention is used, current of electron flow as long
as we can follow the function of a circuit. Likewise knowing whether a
capacitors charge is stored, the plates or the dielectric won't help me
understand why the capacitor seems to allow current to flow right through it.
In fact I can operate as current does flow though the capacitor and when
working with them in actual circuits we assume a capacitor to be an AC short
circuit, albeit a frequency sensitive one.

All of this leads me to quote from Nigel Cook, DC-AC Second Edition, 1993.
In chapter 11, under the summary on capacitance he actually states that the
'charges on the plates produce an electric field...' Sound like he's saying
that the charge is stored on the plates. The last sentence in the paragraph
states...
'The energy in a capacitor is actually stored in the electric field within
the dielectric.' Sounds like it's stored in the dielectric. Now some
interpretation which I would be allowed if I were a student reading this
book, but which could be mistaken. Nothing new, I've been wrong before and I
plan to be wrong again before I go to that great capacitor in the sky to be
fully charged for eternity. :-)
I think both views may be wrong. The energy is stored in the electrostatic
field, not on the plates, not in the dielectric. That certainly would explain
why vacuum capacitors can work. It also agrees with my notion that a
conductor can't really store a charge. Oh, and this also agrees with the
idea that energy is stored in the magnetic field in an inductor, which always
seemed strange to me.

Am I right, is one of the other view right? I really don't give a poop. But I
have an explanation that will satisfy me until someone comes up with a better
one. And I feel that I understand capacitors better now. Maybe I'll take one
out to dinner some time.

Jim



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Re: vacuum and charge

Doug Hale
 

Ah ha, finally the source of confusion.

The charge IS in the plates, the field IS in the dielectric.

The charge and the field ARE NOT the same thing.

An electric field exists between two opposite charges.

Doug Hale


manifold wrote:

Try this link too.
,,sid9_gci211945,00.html

Yes, a vacuum is a dielectric. The dielectric is defined as a "supporter of electrostatic fields". That means, the charge is in the field and the field is in the dielectric and...


The charge is in the dielectric. Even if it's a vacuum. Something for nothing, it just doesn't seem right.




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Re: The need to know!

G Ramasubramani
 

开云体育

Jim,
?
??? Liked your mail. Charge is stored on the plates and the energy in the gap between the plates. This energy results from the field between the positive and negative charges on the plates. The dielectric helps in keeping the charge apart. The maximum amount of charge that can be kept apart depends on the dielectric. In case the amount exceeds this level, then the dielectric breaks down and the capacitor gets discharged real fast. The dielectric also helps in chanellising the field between the plates - this results in different capacitances for different dielectrics if the area of the plates and the distance between them remains the same.
?
Rama

----- Original Message -----
Sent: Monday, October 29, 2001 4:51 PM
Subject: [Electronics_101] The need to know!

Why is as important as What. When If I know a collection of facts but do not
understand why they are so, I have no principles that I can apply in order to
apprehend other facts. So when struggling to understand something I may
appear to be arguing, as in stating that the other person is wrong. While I
have been known to do that some times, usually what I'm doing is trying to
get my mind around the facts.

That I never took college level physics may explain my difficulties, then
again maybe not since I don't know to what extent the issue of 'where a
charge is stored in a capacitor, might be answered by college level physics,
at least as much of it as an EE might take. As a technician I have often had
to just accept some premise, not having the knowledge to question them or to
verify them for that matter. And being pragmatic I see no problem with that
as long is it doesn't interfere with what I may be trying to do.? For
example, who care which convention is used, current of electron flow as long
as we can follow the function of a circuit. Likewise? knowing whether a
capacitors charge is stored, the plates or the dielectric won't help me
understand why the capacitor seems to allow current to flow right through it.
In fact I can operate as current does flow though the capacitor and when
working with them in actual circuits we assume a capacitor to be an AC short
circuit, albeit a frequency sensitive one.

All of this leads me to quote from Nigel Cook, DC-AC Second Edition, 1993.
In chapter 11, under the summary on capacitance he actually states that the
'charges on the plates produce an electric field...' Sound like he's saying
that the charge is stored on the plates. The last sentence in the paragraph
states...
'The energy in a capacitor is actually stored in the electric field within
the dielectric.' Sounds like it's stored in the dielectric. Now some
interpretation which I would be allowed if I were a student reading this
book, but which could be mistaken. Nothing new, I've been wrong before and I
plan to be wrong again before I go to that great capacitor in the sky to be
fully charged for eternity. :-)
I think both views may be wrong. The energy is stored in the electrostatic
field, not on the plates, not in the dielectric. That certainly would explain
why vacuum capacitors can work. It also agrees with my notion that a
conductor can't really store a charge.? Oh, and this also agrees with the
idea that energy is stored in the magnetic field in an inductor, which always
seemed strange to me.

Am I right, is one of the other view right? I really don't give a poop. But I
have an explanation that will satisfy me until someone comes up with a better
one. And I feel that I understand capacitors better now. Maybe I'll take one
out to dinner some time.

Jim



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Re: vacuum and charge

 

Ok, here is part of it. This is the part that I remembered about
permitivity and permeability related to the speed of light. Check
out this link:




1
-----------
_________
C = /
/ uo * eo
\/

Nothing goes faster than the speed of light in a vacuum so at least
we now have the relationship between a constant and another
variable. So now I have to answer this question:

o Can we have a a situation where the permittity decreases while the
permeability increases?

still looking...

--- In Electronics_101@y..., "manifold" <manifold_1@y...> wrote:
No I can't. That one slipped out from memory and not an
attributable
reference. I will try and find support and you can try and find a
way to refute it!

Dang, I'll have to open that physics book yet...

--- In Electronics_101@y..., Sunantoro <SUNANTORO@K...> wrote:
Mr. Manifold (?)
Can you be more specific in stating that dielectric always
INCREASES the
charge stored in a capacitor? I think there must be situations
where change
of dielectric DECREASES it.

SUNAN

-----Original Message-----
From: manifold [SMTP:manifold_1@y...]
Sent: Tuesday, October 30, 2001 7:28 AM
To: Electronics_101@y...
Subject: [Electronics_101] Re: vacuum and charge

Try this link. I think it is a good explaination though it
does not
include the value of the permittivity of free space, 8.85 x 10-12
farad per
meter (F/m).


<
/>
solidstate/dielect.htm
Yes, the dielectric can increase the charge stored in a
capacitor.
Actually, the dielectric always increases the charge stored in a
capacitor.


Re: capacitor discharge practices

Jim Purcell
 

sallehuddin,

U just, connect a resistor parallel to the charged
capacitor, some low value will be fine
It needn't even be a low value. The reason for not just discharging it by
shorting the leads is that short circuit current can damage the capacitor,
not usually an amount that you will notice but a little. This might be more
true of 'lytics. It's a bit like the static on cmos, probably won't kill it
but might shorten it's life.

Jim


The need to know!

Jim Purcell
 

Why is as important as What. When If I know a collection of facts but do not
understand why they are so, I have no principles that I can apply in order to
apprehend other facts. So when struggling to understand something I may
appear to be arguing, as in stating that the other person is wrong. While I
have been known to do that some times, usually what I'm doing is trying to
get my mind around the facts.

That I never took college level physics may explain my difficulties, then
again maybe not since I don't know to what extent the issue of 'where a
charge is stored in a capacitor, might be answered by college level physics,
at least as much of it as an EE might take. As a technician I have often had
to just accept some premise, not having the knowledge to question them or to
verify them for that matter. And being pragmatic I see no problem with that
as long is it doesn't interfere with what I may be trying to do. For
example, who care which convention is used, current of electron flow as long
as we can follow the function of a circuit. Likewise knowing whether a
capacitors charge is stored, the plates or the dielectric won't help me
understand why the capacitor seems to allow current to flow right through it.
In fact I can operate as current does flow though the capacitor and when
working with them in actual circuits we assume a capacitor to be an AC short
circuit, albeit a frequency sensitive one.

All of this leads me to quote from Nigel Cook, DC-AC Second Edition, 1993.
In chapter 11, under the summary on capacitance he actually states that the
'charges on the plates produce an electric field...' Sound like he's saying
that the charge is stored on the plates. The last sentence in the paragraph
states...
'The energy in a capacitor is actually stored in the electric field within
the dielectric.' Sounds like it's stored in the dielectric. Now some
interpretation which I would be allowed if I were a student reading this
book, but which could be mistaken. Nothing new, I've been wrong before and I
plan to be wrong again before I go to that great capacitor in the sky to be
fully charged for eternity. :-)
I think both views may be wrong. The energy is stored in the electrostatic
field, not on the plates, not in the dielectric. That certainly would explain
why vacuum capacitors can work. It also agrees with my notion that a
conductor can't really store a charge. Oh, and this also agrees with the
idea that energy is stored in the magnetic field in an inductor, which always
seemed strange to me.

Am I right, is one of the other view right? I really don't give a poop. But I
have an explanation that will satisfy me until someone comes up with a better
one. And I feel that I understand capacitors better now. Maybe I'll take one
out to dinner some time.

Jim


Re: Light Activated Alarm

angtengchat
 

开云体育

----- Original Message -----
Sent: Tuesday, October 30, 2001 1:32 AM
Subject: Re: [Electronics_101] Light Activated Alarm

Hey ,
?
put a 555 circuit in front of it in monostable mode that will give a desired time for the switch to be on....
?
LOL.... this reminds me of time-bomb !
?
?
--himanshu sharma
----- Original Message -----
Sent: Tuesday, October 30, 2001 12:39 AM
Subject: RE: [Electronics_101] Light Activated Alarm

Jim,
?
Thank you for your response. It seems that the photo transistor is conducting enough to send minimal current through the relay but not enough to activate the switch, so to speak. My problem is that I need the circuit to be such that the alarm continues, even if light is removed from the photo transistor. Could you tell me more about "putting the alarm device in series with the collector and VCC. Again, I appreciate your help.
?
Sincerely,
?
Kenyon Jones
?
-----Original Message-----
From: Jim Purcell [mailto:jpurcell@...]
Sent: Friday, October 26, 2001 5:16 PM
To: Electronics_101@...
Subject: Re: [Electronics_101] Light Activated Alarm

Mounir,
However, if you have the phototransistor turning on/off a relay. And you have a piezo on the other side of the realy, the this resitance shoulder matter. Cause the relay can only be on or off, nothing in between.
Yes, but it the photo transistor is not conducting enough to operate the relay or it's on the raged edge of conduction it might not work as well as it should. I would try dumping the relay and putting the alarm device in series with the collector and Vcc.

Jim

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Re: newbie inquiry

angtengchat
 

<<If in doubt use the gloves. :-).

Which brand of gloves would be good ! What must i do to make sure that the
gloves is Good / insulated. I am always afraid of electricity.


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Re: vacuum and charge

 

No I can't. That one slipped out from memory and not an attributable
reference. I will try and find support and you can try and find a
way to refute it!

Dang, I'll have to open that physics book yet...

--- In Electronics_101@y..., Sunantoro <SUNANTORO@K...> wrote:
Mr. Manifold (?)
Can you be more specific in stating that dielectric always
INCREASES the
charge stored in a capacitor? I think there must be situations
where change
of dielectric DECREASES it.

SUNAN

-----Original Message-----
From: manifold [SMTP:manifold_1@y...]
Sent: Tuesday, October 30, 2001 7:28 AM
To: Electronics_101@y...
Subject: [Electronics_101] Re: vacuum and charge

Try this link. I think it is a good explaination though it
does not
include the value of the permittivity of free space, 8.85 x 10-12
farad per
meter (F/m).


<
/>
solidstate/dielect.htm
Yes, the dielectric can increase the charge stored in a
capacitor.
Actually, the dielectric always increases the charge stored in a
capacitor.


Re: capacitor discharge practices

sallehuddin zam
 

--- epsulon@... wrote:
U just, connect a resistor parallel to the charged
capacitor, some low value will be fine

thank u,


=====


Re: vacuum and charge

Sunantoro
 

Mr. Manifold (?)
Can you be more specific in stating that dielectric always INCREASES the
charge stored in a capacitor? I think there must be situations where change
of dielectric DECREASES it.

SUNAN

-----Original Message-----
From: manifold [SMTP:manifold_1@...]
Sent: Tuesday, October 30, 2001 7:28 AM
To: Electronics_101@...
Subject: [Electronics_101] Re: vacuum and charge

Try this link. I think it is a good explaination though it does not
include the value of the permittivity of free space, 8.85 x 10-12 farad per
meter (F/m).


<>
solidstate/dielect.htm
Yes, the dielectric can increase the charge stored in a capacitor.
Actually, the dielectric always increases the charge stored in a capacitor.


Re: Capator tester

angtengchat
 

开云体育

<
I have not done this. However a good lead would be to use the principle of RC constant.
I normally use a simple sanwa multi-meter to check if a capacitor is still "s".
?

----- Original Message -----
Sent: Tuesday, October 30, 2001 12:59 AM
Subject: Re: [Electronics_101] Capator tester

Michael,
Could anybody point me in the right direction to design a capacitor tester.

I assume you mean an instrument that will measure the capacitance as well as
test whether the capacitor is good. Many years ago I built an Eico kit capacitance
bridge. It use the principle of a wheatstone brige to measure capacitnace. Of
course it was the AC version of the bridge and the user manually ajusted the
bridge for a balance and read the capacitance according to where the pointer
pointed. That kind of instrument used the principle of capacitive reactance.
I think one side of the bridge consisted of one known and the unknown
capacitance and the other a fixed and a variable resistance. I confess
that Ihave not read any description of how the modern solid state
instruments work but I guess they are just automated implementations
of the old bridge circuits. In any they most likely depend on passing
AC through the capacitor and determining capacitance accoring to
a voltage drop across a component.


Jim

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Re: vacuum and charge

 

Try this link too.

,,sid9_gci211945,00.html

Yes, a vacuum is a dielectric. The dielectric is defined as
a "supporter of electrostatic fields". That means, the charge is in
the field and the field is in the dielectric and...


The charge is in the dielectric. Even if it's a vacuum. Something
for nothing, it just doesn't seem right.


capacitor discharge practices

 

I'm reading another basic book to get two points of view plus the little
extras each book kind of offers. All the beginning books warn about cap.
discharge, but they don't tell safe methods to discharge them. I would like
to hear capacitor discharge practices so I can be safe.


Re: newbie inquiry

angtengchat
 

开云体育

From: av1a@...
Sent: Tuesday, October 30, 2001 12:29 AM
Subject: RE: [Electronics_101] Re: newbie inquiry

Please tell me that 12VDC ~ 2Amps ~ 230 Watts (PC power Supply) don't kill , as i've tried it. (ahhhhh)
?
12VDC ~ 2Amps ~ 230 Watts , you should not be bothered about 2 amps, it should therefore read 12VDC ~? 230 Watts
?
12VDC will never kill a person irregardless of wattage ratings!
?
Does anyone have a chart that tells me when to touch & when to wear rubber gloves
imran
?
1) consult a doctor to determine what is the min current limit to electrocute a person.
2) then use ohms law V= IR (R = your body resistance which varies from person to person) to determine the min voltage that will electrocute a person.
3) Then W=IV to determine the min wattage that could electrocute a person.
?
Then your chart should be?the combination of Watts and Voltage. (forget about amps).that could electrocute a person.
?
-----Original Message-----
From: Jonathan Luthje [mailto:jluthje@...]
Sent: Monday, October 29, 2001 6:32 AM
To: Electronics_101@...
Subject: Re: [Electronics_101] Re: newbie inquiry

Mounir,
??? Yes stun guns produce many thousands of volts - an automotive ignition
system can produce 75-100kV - a LOT of voltage. The primary reason that high
voltages (such as 110v or 240v as used in your house wiring) do kill is
because of the current path. The heart is the most susceptable organ in the
body to electrical impulses and the disruption of the same.

Thousands of volts can safely flow (though not without pain) through, say
your middle and index fingers without doing a lot of damage.

Don't get me wrong here - given enough current flow and voltage - it could
easily remove a hand or a couple of fingers - lower currents such as those
produced by an ignition system do not have sufficient amperage to cause
severe burns - although they can "spot burn" the skin - not enough to
notice.

As I was saying earlier - the primary cause of death due to electrocution is
heart failure as a result of current flowing through the heart - 0.0001
amperes is enough to stop the heart - but in the case of a stun gun the
current flows between the two electrodes, and so doesn't get to travel to
the heart. This is the reason for the old rule when it comes to working with
high voltages - keep one hand in your pocket and ensure that you have rubber
soled (insulated) shoes on. In this way the chance is highly reduced that a
high voltage will flow from one arm to the other (and hence through your
heart), or to ground (earth) through your legs, and again this gives a
higher probablity of the current flowing through your heart.

High frequency electricity also behaves quite differently to lower frequency
electricity (say 20kHz compared to 50Hz or 0Hz (DC)) - higher frequency
electricity tends to stick to the outside of your body (and such has been
demonstrated many a time by the maniacs (no offence anyone :-) that operate
Tesla coils having many millions of volts potential and sticking their hand
on the output dome or toroid - the electricity flows over the outside of
their body.

Not that I would ever attempt such a stunt myself ...

Hope this enlightens you a little


Regards,


J0n






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Re: vacuum and charge

 

Try this link. I think it is a good explaination though it does not
include the value of the permittivity of free space, 8.85 x 10-12
farad per meter (F/m).


solidstate/dielect.htm

Yes, the dielectric can increase the charge stored in a capacitor.
Actually, the dielectric always increases the charge stored in a
capacitor.



--- In Electronics_101@y..., Doug Hale <doughale@x> wrote:

Mark Kinsler wrote:

Vacuum has an inherent dielectric constant, known as the
permittivity of a
vacuum (or of 'free space'.) It also has an inherent inductance,
known as
the permeability of vacuum. These are values you can look up.
They are
both very close to what we find in air at atmospheric pressure.

A vacuum capacitor does indeed store charge in its vacuum, odd as
that may
seem. They typically have very small capacitance values, just as
we find in
air-dielectric capacitors. The air doesn't store the charge in an
air-dielectric capacitor, of course: you can blow the air out from
between
the plates and the charge will remain.
The air dielectric capacitor is the finest example of why the
charge is
in the plate, not the dielectric -
and how do the plates know that the dielectric is a vacuum and
therefor
"the vacuum stores the charge" or that the dielectric is air and
since
the air can be blown away, the plate needs to store the charge?

It is basic material physics - plates store charge - dielectrics
insulate the charges.


This leads to another way to explain things. If a capacitor is
charged,
one plate has a negative charge and the other plate has a positive
charge. If the dielectric stored the charge, how does the
dielectric
keep the negative charges away from the positive charges?

That IS the purpose of the dielectric - to insulate the charges
opposing
charges on the plates from one another.


Doug Hale



There are lots easier ways to determine the electrical qualities
of air at
low pressures than the one suggested. While a balloon experiment
would be
fun, I've done the same thing with a small vacuum pump, my trusty
ignition-coil high-voltage power supply and a suitably-rigged
jelly jar.

What you're looking for is something called the Paschen curve for
air. One
axis of the Paschen curve plot is the voltage and the other is the
pressure--though I think that there's a provision for the
electrode gap in
there somewhere (memory fails at times.) It turns out that this
curve is
fairly linear near atmospheric pressure. The voltage necessary
for arc
initiation is lowest at a partial vacuum. It rises for very high
vacuums
and for very high pressures.

M Kinsler

512 E Mulberry St. Lancaster, Ohio USA 740 687 6368



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Re: vacuum and charge

G Ramasubramani
 

开云体育

Doug,

>> That IS the purpose of the dielectric - to insulate the charges opposing
>> charges on the plates from one another.
?
Well said.
?
Rama



Re: newbie inquiry

Keith Messent
 

IIRC, the dangerous levels are such as would deliver energy of 10 Joules
along a path through the Heart, i.e. across the Thorax or via Head to
Foot. A large capacitance could deliver this!
Keith Messent, Skipton, UK

----- Original Message -----
From: Jim Purcell <jpurcell@...>
To: <Electronics_101@...>
Sent: Monday, 29 October, 2001 05:30 PM
Subject: Re: [Electronics_101] Re: newbie inquiry


You mean you are writing from 'the other side', i.e. you
are dead? What can shock you depends on many factors.
(snipped)
If in doubt use the gloves. :-). If the voltage is less
than 100 you can probably get by without the gloves. If you
avoid completing any circuits it is also possible in some
cases to avoid shocks. Sometimes equipment must be operated
with the dangerous components exposed, always assume that
such devices can bite you.
Avoid touching them with both
hands. The dangerous path is across your heart. The general
rule is, turn it off, but if you can't, keep one hand behind
you.


Re: vacuum and charge

Doug Hale
 

Mark Kinsler wrote:

Vacuum has an inherent dielectric constant, known as the permittivity of a vacuum (or of 'free space'.) It also has an inherent inductance, known as the permeability of vacuum. These are values you can look up. They are both very close to what we find in air at atmospheric pressure.

A vacuum capacitor does indeed store charge in its vacuum, odd as that may seem. They typically have very small capacitance values, just as we find in air-dielectric capacitors. The air doesn't store the charge in an air-dielectric capacitor, of course: you can blow the air out from between the plates and the charge will remain.
The air dielectric capacitor is the finest example of why the charge is in the plate, not the dielectric -
and how do the plates know that the dielectric is a vacuum and therefor "the vacuum stores the charge" or that the dielectric is air and since the air can be blown away, the plate needs to store the charge?

It is basic material physics - plates store charge - dielectrics insulate the charges.


This leads to another way to explain things. If a capacitor is charged, one plate has a negative charge and the other plate has a positive charge. If the dielectric stored the charge, how does the dielectric keep the negative charges away from the positive charges?

That IS the purpose of the dielectric - to insulate the charges opposing charges on the plates from one another.


Doug Hale



There are lots easier ways to determine the electrical qualities of air at low pressures than the one suggested. While a balloon experiment would be fun, I've done the same thing with a small vacuum pump, my trusty ignition-coil high-voltage power supply and a suitably-rigged jelly jar.

What you're looking for is something called the Paschen curve for air. One axis of the Paschen curve plot is the voltage and the other is the pressure--though I think that there's a provision for the electrode gap in there somewhere (memory fails at times.) It turns out that this curve is fairly linear near atmospheric pressure. The voltage necessary for arc initiation is lowest at a partial vacuum. It rises for very high vacuums and for very high pressures.

M Kinsler

512 E Mulberry St. Lancaster, Ohio USA 740 687 6368



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