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Hello Echidna, Crossover Distortion -------------------- I calculated the formula with Fourier series and approximation. sin(x) = x-1/3*x^3 1-x^2 = 1-2*x THD = 100%*2*pi*sqrt(1/3*(D/T)^3)

Yes, I found 25*(D/T)^2 by trial. Running simuations that give me THD, I see it fits perfectly with D/T from 0.02 to 0. Yes, I meant "unable". Now, I understand better. The 25*(D/T)^2 is quite normal.

In message <kkdr4u+gvv5@...>, dated Sun, 14 Apr 2013, Echidna <mchambin@...> writes: Thanks. I just wanted to prevent others being confused. Agreed. I will try using Mathcad, but I can't

Hi All, is it possible to step a resistor over time? Right now if I use the step command like this: .step param R 100 1000 100 .tran 0 1ms 0 1 I end up with a bunch of parallel horizontal lines. What

Indeed, I found 25*(D/T)^2 by trial. Running simulations that gave me THD values for various D values. I have uploaded the .asc file of that simulaton. "enable" is a spelling mistake. I meant

In message <kkdlr2+p199@...>, dated Sun, 14 Apr 2013, MOHAMMAD A MAKTOOMI <amaktoomamu@...> writes: It will be ignored, which is equivalent. I don't see a solution if R2 varies at

In message <kkckve+t28o@...>, dated Sat, 13 Apr 2013, Echidna <mchambin@...> writes: I think you mean you found 25*(D/T)^2 by trial. This can be misleading. I once found a power function

Hello John, Actually, a DC input voltage is present. But, I don't know if it will be ground in AC analysis.If that's grounded then how could I have output (ignore offsets at this moment).

In message <kkdb2u+pa7l@...>, dated Sun, 14 Apr 2013, MOHAMMAD A MAKTOOMI <amaktoomamu@...> writes: Varying the value of R2, with no other input signal, doesn't produce any output,

Thank you, Andy for your hints. But, in '.AC' we need to have an AC voltage or current source. Here, I don't have any such thing (as I wish to vary the frequency of R2, NOT that of any source), so how

MOHAMMAD A MAKTOOMI <amaktoomamu@...> wrote: Note: In your circuit, you may need to decrease the maximum timestep down to about 10ns. (.tran 0 0.1m 0 10n) The output waveform is highly distorted

Janiel Feng <m_zhao12@...> wrote: First, try some of the FAQ files located here: Files > FAQ (http://tech.groups.yahoo.com/group/LTspice/files/%20FAQ/) In particular, look at

Janiel Feng <m_zhao12@...> wrote: You should have created a new message topic with its own Subject, rather than hijacking someone else's question. Response forthcoming with a new Subject line.

Hi, I imported models from Pspice to LTspice from TI and Analog Devices. But most of them have Convergence Problem. Is there anybody know how to solve this problem? Thanks. Janiel

Dear Michael, Thanks. Of course example but Helmut make sense (a modified version is here: http://groups.yahoo.com/group/LTspice/files/%20Temp/ni-opamp2.asc) in time domain. But, I don't want to be in

The quickest way to get a frequency response is to use an .AC analysis, rather than .TRANsient. Then you can sweep and plot output amplitude versus frequency. The thing to always remember about .AC

Hi Maktoomi Helmut example is absolutely right. This is because a quick analysis of the circuit you have given shows the following:- Vo/Vin = R2(f)/R1 . It follows that Vo= [R2(f)/Rin]*Vin = Iin*R2(f)

This is likely a MS-Windows problem, but you haven't given us nearly enough information to say for sure. You probably put a file in a directory owned by Windows (perhaps a subdirectory of C:/Program

Hello. How to calculate, using maths and definitions, the THD of this signal: A sine with a small dent at the crossovers. S(t) = 0 for 0 < t < D where D is much smaller than T S(t) = sin omega*t for D