Re: Oddity in Behavioural Voltage Source

F.an · 2025-05-16T01:31:22-07:00

if 0< {AMP}*V(D1)<10, G2 output {AMP}*V(D1), based on your params, this part is 10 times "higher" of amplitude value of the "source" D1. I assume you did not divide 10 (AMP) when you probe the G2.

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Re: Oddity in Behavioural Voltage Source

F.an Member Profile All Messages By This Member #160440 if? 0< {AMP}V(D1)<10, ? G2 output {AMP}V(D1), based on your params, this part is 10 times "higher" of amplitude value of the "source" D1. ? I assume you did not divide 10 (AMP) when you probe the G2.

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Re: Oddity in Behavioural Voltage Source